Unknown (T-test)
Test the claim that
: 
<
80 for these data using 
=
0.10:
|
60 |
70 |
75 |
55 |
80 |
55 |
|
65 |
40 |
80 |
70 |
80 |
95 |
|
120 |
90 |
75 |
85 |
80 |
60 |
Note that 
is
80.
First enter
the data in 
by pressing STAT and selecting 1:Edit by pressing ENTER.
The result is shown below
Press STAT, then RIGHT ARROW twice to TESTS. Press 2 to
select 2:T-Test. If Data is not already highlighted, LEFT ARROW
to highlight it, and then press ENTER to select the data mode. ARROW
DOWN once and enter 80
next to 
:.
Make sure the defaults of
for List: and 1 for Freq: are also listed.
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ARROW
DOWN to :.
Use the arrow keys to highlight <,
since the claim being tested is <
80, and press ENTER. ARROW
DOWN to select Calculate, and then press ENTER. The
results are shown below.
Conclusions based on t-value:
The test t value shown above is t = -1.381. Using a t distribution
table for a 1-tailed test with=
0.10 and d.f.= 17, we find that the critical t value is t =
-1.333.
This is a left-tailed
test, so since -1.381 < -1.333, we are in the rejection region, so
reject :
80, and accept the alternative hypothesis :<
80.
Conclusions based on P-value:
The test p value shown above is p = 0.0926361139. The decision is to reject
: 80, since 0.0926361139 < 0.10; that is, p < .
Test the claim :
= 8
when 
= 0.6, 
= 8.2, and n = 25 using =
0.05. We use :
8.
Press STAT, then RIGHT ARROW twice to TESTS. Press 2 to select 2:T-Test.
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If STATS is not highlighted,
ARROW RIGHT once and press ENTER to select STATS. ARROW
DOWN once and enter the value of 8 for .
ARROW DOWN once and enter 8.2 for .
ARROW DOWN once and enter .6 for .
ARROW DOWN once again, and enter 25 for n.
Now we must choose which test. Since
this is a two-tailed test, ARROW DOWN once to :
then use the LEFT or RIGHT ARROW to select ,
then press ENTER. ARROW
DOWN one last time to Calculate and then press ENTER. The
results are shown below.
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Conclusions based on t-value:
The test t value shown above is t = 1.667. Using a t-distribution table
for =
0.05, d.f.= 24 and the fact that this is a two-tailed test, we find that
the critical value is t = 2.064. Thus, the rejection region is t <
-2.064 or t > 2.064. Since -2.064 < 1.667 < 2.064, the
decision is that we cannot reject :
= 8.
Conclusions based
on P-value:
The test p value shown about is p = 0.1085801058. Thus, we cannot reject
:
= 8 since 0.1085801058 > 0.05
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